Problem :
zip([iterable, ...])
This function returns a list of tuples. The i th tuple contains the i th element from each of the argument sequences or iterables.
If the argument sequences are of unequal lengths, then the returned list is truncated to the length of the shortest argument sequence.
Sample Code :
>>> print zip([1,2,3,4,5,6],'Hacker') [(1, 'H'), (2, 'a'), (3, 'c'), (4, 'k'), (5, 'e'), (6, 'r')] >>> >>> print zip([1,2,3,4,5,6],[0,9,8,7,6,5,4,3,2,1]) [(1, 0), (2, 9), (3, 8), (4, 7), (5, 6), (6, 5)] >>> >>> A = [1,2,3] >>> B = [6,5,4] >>> C = [7,8,9] >>> X = [A] + [B] + [C] >>> >>> print zip(*X) [(1, 6, 7), (2, 5, 8), (3, 4, 9)]
Task :
Your task is to compute the average scores of each student.
 |
| fig : Zipped in python - Hacker Rank Solution |
The format for the general mark sheet is:
Student ID → ___1_____2_____3_____4_____5__ Subject 1 | 89 90 78 93 80 Subject 2 | 90 91 85 88 86 Subject 3 | 91 92 83 89 90.5 |______________________________ Average 90 91 82 90 85.5
Input Format :
The next X lines contains the space separated marks obtained by students in a particular subject.
Constraints :
- 0 < N <= 100
- 0 < X <= 100
Output Format :
Print the averages of all students on separate lines.The averages must be correct up to 1 decimal place.
Sample Input :
5 3 89 90 78 93 80 90 91 85 88 86 91 92 83 89 90.5
Sample Output :
90.0 91.0 82.0 90.0 85.5
Explanation :
Marks obtained by student 1: 89 90 91
Average marks of student 1:
270 / 3 = 90.0
Marks obtained by student 2: 90 91 92Average marks of student 2:
273 / 3 = 91.0
Marks obtained by student 3: 78 85 83Average marks of student 3:
246 / 3 = 82.0
Marks obtained by student 4: 93 88 89Average marks of student 4:
270 / 3 = 90.0
Marks obtained by student 5: 80 86 90.5Average marks of student 5:
256.5 / 3 = 85.5