Problem :

any()
This expression returns True if any element of the iterable is true.

If the iterable is empty, it will return False.

Code :

>>> any([1>0,1==0,1<0])
True
>>> any([1<0,2<1,3<2])
False

all()

This expression returns True if all of the elements of the iterable are true. If the iterable is empty, it will return True.

Code :

>>> all(['a'<'b','b'<'c'])
True
>>> all(['a'<'b','c'<'b'])
False

Task :

You are given a space separated list of integers. If all the integers are positive, then you need to check if any integer is a palindromic integer.

Input Format :

The first line contains an integer N. N is the total number of integers in the list.

The second line contains the space separated list of N integers.

Constraints :

0 < N < 100

Output Format :

Print True if all the conditions of the problem statement are satisfied. Otherwise, print False.

Sample Input :

5
12 9 61 5 14

Sample Output :

True

Explanation :

Condition 1: All the integers in the list are positive.
Condition 2: 5 is a palindromic integer.
Hence, the output is True.
Can you solve this challenge in 3 lines of code or less?

There is no penalty for solutions that are correct but have more than 3 lines.

Any or All in python - HackerRank Solution